updated calc iii notes
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@@ -44,3 +44,19 @@ Theorem:
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\text{If } D(a,b) < 0 \text{, there exists a saddle point at }(a,b) \text{.}\\
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\text{If } D(a,b) < 0 \text{, there exists a saddle point at }(a,b) \text{.}\\
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\text{If } D(a,b) = 0 \text{ the test is inconclusive.}
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\text{If } D(a,b) = 0 \text{ the test is inconclusive.}
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\]
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\]
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## Lagrange Multipliers
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Theorem:
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\[
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\text{Let } f \text{ be a differentiable function in } R^2 \text{ that contains curve } C \text{ given by } g(x,y) = 0. \text{ Assume } f \text{ has a local extrema on } C \text{ at point } P(a,b). \text{ Then } \nabla f(a,b) \text{ is orthogonal to the tangent line of } C \text{ at } P. \text{ Assuming } \nabla g(a,b) \neq 0, \text{ then there is a real number } \lambda \text{, or lagrange multiplier, such that } \nabla f(a,b) = \lambda \nabla g(a,b).
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\]
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To find absolute extremas using lagrange multipliers:
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1. Find the gradient of \(f\)
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2. Find the gradient of \(g\)
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3. Set \(\nabla f(x,y) = \lambda \nabla g(x,y)\)
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4. Solve the system for \(x\) and \(y\) of \(\nabla f(x,y) = \lambda \nabla g(x,y)\) and \(g(x,y) = 0\).
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5. Evaluate the points you've found in \(f(x,y)\). The largest value is the absolute maximum. The smallest value is the absolute minimum.
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@@ -11,9 +11,15 @@
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},
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},
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output: {
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output: {
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displayAlign: 'left',
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displayAlign: 'left',
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displayIndent: '0.5in',
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displayIndent: '0.25in',
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displayOverflow: 'linebreak'
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displayOverflow: 'linebreak'
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},
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},
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linebreaks: {
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inline: true,
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width: '100%',
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lineleading: '0.2',
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LinebreakVisistor: '-'
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}
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};
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};
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</script>
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</script>
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